思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
And if you’ve been hoping to treat yourself to a robot vacuum, as of March 3, you can find a great deal on the Shark AV2501AE AI at Amazon. This model is currently down to $299 from $649, saving you $350 on list price.
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Lazy evaluation also unlocks infinite collections — you can define an infinite
By providing an opaque hint and not providing the word list, Strands creates a brain-teasing game that takes a little longer to play than its other games, like Wordle and Connections.