Note: the questions below are taken from the same JEE Mains paper solved above.
If we ignore the fact that exceptions in Java are typed, all that’s actually happening here is that every time we enter a try block, the compiler records in memory the location of the instruction corresponding to the start of the catch block. As we keep calling more functions, some of them might have try blocks of their own, and those are added onto a stack—a shorter stack than the actual call stack, since not all functions have a try/catch. When an exception is thrown, instead of looking up the location the function is supposed to return to, we consult the stack to find the topmost catch block, and jump straight there. We’ve just done a return that has skipped over multiple functions all in one go.
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